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Home » Update Alert: Halo on PS5 Just Got Unbelievably Better – Watch Here! - Dachbleche24

Update Alert: Halo on PS5 Just Got Unbelievably Better – Watch Here! - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 = 3^4 \cdot 5^2

📌 The number of positive divisors is $ (4+1)(2+1) = 15 $, so there are 15 positive divisor pairs $ (a, b) $ with $ a > 0, b > 0 $, and another 15 with $ a < 0, b < 0 $, giving 30 total integer divisor pairs (since $ a $ and $ b $ can both be negative).

📌 But we only count pairs where $ a $ and $ b $ have the same parity. Since 2025 is odd, all its divisors are odd. Therefore, $ a $ and $ b $ are both odd in every factor pair, and the sum and difference are even. So all 30 pairs yield integer $ (x, y) $.

📌 However, each solution $ (x, y) $ corresponds to a unique pair $ (a, b) $, and since $ x $ and $ y $ are determined uniquely, and the hyperbola is symmetric, we must check for duplicates. But since $ (a, b) $ and $ (b, a) $ would give different $ x $ and $ y $, and both are included, all 30 pairs produce valid, distinct lattice points.

📌 For example:

📌 If $ a = 1, b = 2025 $, then $ x = 1013, y = 1012 $

📌 If $ a = 2025, b = 1 $, then $ x = 1013, y = -1012 $

📌 These are distinct points.

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\frac{1}{k(k+1)(k+2)} = \frac{1}{2k} - \frac{1}{k+1} + \frac{1}{2(k+2)...
The sum becomes:
\sum_{k=1}^{50} \left( \frac{1}{2k} - \frac{1}{k+1} + \frac{1}{2(k+2)}...
Reindex the sums:
= \frac{1}{2} \left( \sum_{k=1}^{50} \frac{1}{k} \right) - \left( \sum...
Combine terms:
= \frac{1}{2} \left( 1 + \frac{1}{2} + \sum_{k=3}^{50} \frac{1}{k} \ri...
= \frac{1}{2} + \frac{1}{4} - \frac{1}{2} - \frac{1}{51} + \frac{1}{2}...
\frac{1}{4} - \frac{1}{102} + \frac{1}{104} = \frac{1}{4} - \frac{52 -...
Final answer: $\boxed{\dfrac{1325}{5304}}$Question:

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