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Home » Thus, the ratio is $ oxed\sqrt3 $. - Dachbleche24

Thus, the ratio is $ oxed\sqrt3 $. - Dachbleche24

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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Final answer: $ \boxed{-1} $
The tangent of $ 45^\circ $ is defined as the ratio of sine to cosine...
\tan 45^\circ = \frac{\sin 45^\circ}{\cos 45^\circ}
\sin 45^\circ = \cos 45^\circ = \frac{\sqrt{2}}{2}
Final answer: $ \boxed{1} $
Question: The hypotenuse of a right triangle is $ h $, and the radius...
The area of a right triangle with inradius $ r $ and hypotenuse $ h $...
A_{\text{triangle}} = r \cdot \frac{a + b + h}{2}
But in a right triangle, the inradius is related to the sides $ a, b,...
r = \frac{a + b - h}{2}

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