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Home » The final answer is $\boxed150$. - Dachbleche24

The final answer is $\boxed150$. - Dachbleche24

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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After re-evaluation, realize: the problem may expect solving the quadr...
Since no integer solution, but in real context, perhaps accept \( n =...
Wait — perhaps I miscalculated the sum formula.
General: \( S_n = \frac{n}{2}[2a + (n-1)d] = \frac{n}{2}[6 + (n-1)2] =...
So \( n(n+2) = 210 \).
\( n = \frac{ -2 \pm \sqrt{4 + 840} }{2} = \frac{ -2 \pm \sqrt{844} }{...
\( \sqrt{844} = \sqrt{4 \times 211} = 2\sqrt{211} \).
\( \sqrt{211} \approx 14.525 \), so \( n \approx \frac{27.05}{2} = 13....
Since \( n \) must be integer, and 13 gives 195, 14 gives 224, no solu...
But the problem likely has a typo.

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A company manufactures two products, A and B. Product A requires 3 hou...
To maximize profit, let x be the number of Product A units and y be th...
Constraint: 3x + 5y ≤ 120
Profit: P = 40x + 60y
We use integer linear programming logic: test corner points of feasibl...
If y = 0: x = 40 → P = 40×40 = $1600
If x = 0: y = 24 → P = 60×24 = $1440

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