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Home » t = rac10 \pm 2\sqrt718 = rac5 \pm \sqrt79. - Dachbleche24

t = rac10 \pm 2\sqrt718 = rac5 \pm \sqrt79. - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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5**Question:** An isosceles triangle has a base of 10 cm and a height...
The area of a triangle is given by the formula:
A = \frac{1}{2} \times \text{base} \times \text{height}
Initially, the base is 10 cm and the height is 8 cm, so the initial ar...
A_1 = \frac{1}{2} \times 10 \times 8 = 40 \text{ cm}^2
When the base is reduced by 2 cm, the new base becomes \(10 - 2 = 8\)...
A_2 = \frac{1}{2} \times 8 \times 8 = 32 \text{ cm}^2
\Delta A = A_1 - A_2 = 40 - 32 = 8 \text{ cm}^2
Thus, the area decreases by \(\boxed{8}\) square centimeters.
Question:** A circle is inscribed in a square with side length 10 cm....

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