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Home » Solving for \(x\), \(3x = 69\) so \(x = 23\). - Dachbleche24

Solving for \(x\), \(3x = 69\) so \(x = 23\). - Dachbleche24

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 Multiply both sides by \( a \):

📌 a^2 + 1 = 2a \quad \Rightarrow \quad a^2 - 2a + 1 = 0 \quad \Rightarrow \quad (a - 1)^2 = 0.

📌 So, \( a = 1 \). Thus:

📌 \frac{x + 2}{x - 2} = 1 \quad \Rightarrow \quad x + 2 = x - 2,

📌 which simplifies to \( 2 = -2 \), a contradiction. This implies no solution unless we consider domain restrictions.

📌 But solving directly from the original:

📌 Multiply both sides by \( (x - 2)(x + 2) = x^2 - 4 \):

📌 2x^2 + 8 = 2x^2 - 8.

🔥 Popular Posts

\( h^{5/2} = 12^{5/2} - \frac{288}{25\pi} \cdot \frac{5}{2} = 12^{5/2}...
\( 12^{5/2} = (12^2)\sqrt{12} = 144 \cdot 2\sqrt{3} \approx 144 \cdot...
Subtract \( \frac{28.8}{\pi} \approx 9.17 \), so \( h^{5/2} \approx 48...
Actually: \( h^{5/2} = 498.816 - 9.17 = 489.65 \) → \( h = (489.65)^{2...
\( 489.65^{0.4} \): \( \ln(489.65) \approx 6.19 \), \( 0.4 \times 6.19...
But more accurately: let \( u = h^{5/2} \), \( u = 498.816 - 9.17 = 48...
\( 489.646^{0.4} = (e^{\ln 489.646})^{0.4} = e^{0.4 \times 6.189} = e^...
Verify: \( 11.85^{2.5} = 11.85^2 \cdot \sqrt{11.85} \approx 140.2 \cdo...
Adjust: try \( h = 12.1 \): \( h^{5/2} = 12.1^2 \cdot \sqrt{12.1} = 14...
Interpolate: \( h \approx 12.0 - \frac{9.17}{2(12^{5/2} \cdot \frac{5}...

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