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Home » Solution: We are given $ r(t) = \sqrt(t - 8)^2 $. - Dachbleche24

Solution: We are given $ r(t) = \sqrt(t - 8)^2 $. - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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\( x^2 = 4x - x^2 \Rightarrow 2x^2 - 4x = 0 \Rightarrow 2x(x - 2) = 0...
So, \( x = 0 \) and \( x = 2 \).
The area is \( \int_0^2 [(4x - x^2) - x^2] \, dx = \int_0^2 (4x - 2x^2...
Integrate:
\( \left[2x^2 - rac{2}{3}x^3
ight]_0^2 = \left(2(4) - rac{2}{3}(8)
ight) - 0 = 8 - rac{16}{3} = rac{24}{3} - rac{16}{3} = rac{8}{3} \...
So, the enclosed area is \( rac{8}{3} \) square units.
A population of bacteria doubles every 3 hours. If the initial populat...
Use exponential growth: \( P(t) = P_0 \cdot 2^{t/T} \), where \( T = 3...

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