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Home » P(T|F) = \fracP(FP(F) = \frac0.150.19 \approx 0.7895 - Dachbleche24

P(T|F) = \fracP(FP(F) = \frac0.150.19 \approx 0.7895 - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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But \(r^2 + z^2 = x^2 + y^2 + z^2\), and \(r = \sqrt{x^2 + y^2}\), so:
Now square both sides carefully:
This is not a sphere â it's a **quartic surface**. But wait: earlier...
Let \(r = \sqrt{x^2 + y^2}\), so:
r^2 + z^2 = c r \Rightarrow r^2 - c r + z^2 = 0
This is a **circular cylinder**? No â it's quadratic. But geometrica...
ho = c \sin\phi\) is a **sphere tangent to the xy-plane** at the origi...
Standard result: In spherical coordinates, \(
ho = 2a \sin\phi\) represents a sphere of radius \(a\) centered at \((...
Compare: \(

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