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📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 \( x \) について解きます：\( x = \frac{4}{2} = 2 \)。

📌 初項から \( n \) 項までの和が \( S_n = 3n^2 + 5n \) で与えられる数列の第 \( n \) 項を求めます。

📌 第 \( n \) 項 \( a_n = S_n - S_{n-1} \) です。

📌 \( S_{n-1} = 3(n-1)^2 + 5(n-1) = 3(n^2 - 2n + 1) + 5n - 5 = 3n^2 - 6n + 3 + 5n - 5 \) です。

📌 簡略化します：\( S_{n-1} = 3n^2 - n - 2 \)。

📌 したがって、\( a_n = (3n^2 + 5n) - (3n^2 - n - 2) = 6n + 2 \) です。

📌 初速度 \( 50 \) m/sで、水平面に対して \( 30^\circ \) の角度で射出された射体の水平到達距離を求めます。\( g = 9.8 \) m/s² とします。

📌 射程の公式は \( R = \frac{v^2 \sin(2\theta)}{g} \) です。

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