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goku super saiyan 4 dragon ball daima - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 Using \( s = ut + \frac{1}{2}at^2 \), with \( u = 0 \), \( v = at = 30 \), so \( a = 3 \, \text{m/s}^2 \), and \( t = 10 \):

📌 s = 0 + \frac{1}{2}(3)(10)^2 = \frac{1}{2} \cdot 3 \cdot 100 = 150 \, \text{m}

📌 The distance traveled is 150 meters.

📌 A circle has circumference \( 20\pi \) cm. Find the area of a sector with central angle \( 72^\circ \).

📌 First, find radius: \( C = 2\pi r = 20\pi \implies r = 10 \, \text{cm} \).

📌 Sector area: \( \frac{\theta}{360} \cdot \pi r^2 = \frac{72}{360} \cdot \pi \cdot 100 = \frac{1}{5} \cdot 100\pi = 20\pi \, \text{cm}^2 \).

📌 The area of the sector is

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#### 1650
A cone with height 12 cm and base radius 5 cm is filled with water. Th...
Volume of cone: \( V = \frac{1}{3}\pi r^2 h \); by similar triangles,...
So \( V = \frac{1}{3}\pi \left(\frac{5}{12}h\right)^2 h = \frac{25\pi}...
Rate of change: \( \frac{dV}{dt} = -0.2\sqrt{h} \); but \( \frac{dV}{d...
Thus, \( \frac{25\pi}{144} h^2 \frac{dh}{dt} = -0.2 \sqrt{h} \) → \( \...
Separate variables and integrate from \( h = 12 \) at \( t = 0 \) to \...
\( \int_{12}^{h} h^{3/2} dh = -\frac{28.8}{25\pi} \int_0^{10} dt \)
\( \left[ \frac{2}{5} h^{5/2} \right]_{12}^{h} = -\frac{28.8}{25\pi} \...
\( \frac{2}{5}(h^{5/2} - 12^{5/2}) = -\frac{288}{25\pi} \)

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