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Home » Cuando $ X = 0 $, $ Y \geq 15 $ - Dachbleche24

Cuando $ X = 0 $, $ Y \geq 15 $ - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 Complete the square:

📌 x^2 - 6x = (x - 3)^2 - 9

📌 Substitute back:

📌 9((x - 3)^2 - 9) = 9(x - 3)^2 - 81

📌 Complete the square for \( y \):

📌 Factor out \(-16\) from \( y \)-terms:

📌 -16(y^2 - 4y)

📌 y^2 - 4y = (y - 2)^2 - 4

🔥 Popular Posts

12^2 = 144 < 200
Check \( v = 15 \) (next multiple):
15^2 = 225 > 200 \quad \text{(not valid)}
Since 15 exceeds the limit, the largest valid multiple is 12.
Therefore, the largest possible value of \( v \) is \(\boxed{12}\).
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Let \( N = 100a + 10b + 3 \). We require \( N \equiv 0 \pmod{9} \). Si...
N \equiv a + b + 3 \pmod{9}
We need:

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