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can you play ps4 games on ps5 - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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So 21 sequences with no two consecutive 3s.
Total sequences: $ 2^6 = 64 $
Thus, number with **at least one** "33" is $ 64 - 21 = 43 $
Therefore, the answer is $ \boxed{43} $.
\boxed{43}**Question: A vector \(\mathbf{v}\) satisfies \(\mathbf{v} \...
Given \(\mathbf{v} \times \mathbf{b} = \begin{pmatrix} 0 \\ 3 \\ -4 \e...
The cross product \(\mathbf{v} \times \mathbf{b}\) is:
\mathbf{v} \times \mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j}...
Set this equal to \(\begin{pmatrix} 0 \\ 3 \\ -4 \end{pmatrix}\):
2v_2 = 0 \\

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