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Home » But $ \frac144256 = \frac5496 = \frac2748 = \frac916 $ — yes. - Dachbleche24

But $ \frac144256 = \frac5496 = \frac2748 = \frac916 $ — yes. - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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Third term: $ A + 2d $, first: $ A $, so ratio:
\frac{A + 2d}{A} = 1 + 2\frac{d}{A} = 1 + 2\frac{1}{x} = 1 + \frac{2x}...
Take positive root for real chance (positive terms): $ x = \frac{-21 +...
But from quadratic: $ 14x^2 + 42x + 27 = 0 $. Product of roots $ \frac...
Let roots be $ r_1, r_2 $, then $ \frac{A + 2d}{A} = 1 + 2\frac{d}{A}...
Let $ y = \frac{1}{x} $, then from $ 14x^2 + 42x + 27 = 0 $, divide by...
$ 14 + 42y + 27y^2 = 0 \Rightarrow 27y^2 + 42y + 14 = 0 $.
y = \frac{-42 \pm \sqrt{1764 - 1512}}{54} = \frac{-42 \pm \sqrt{252}}{...
We want positive ratio. Try $ y = \frac{-7 + \sqrt{7}}{9} \approx \fra...
Wait — the original assumption about ordering may be wrong. Try symmet...

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