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Home » Be the Life of the Holiday Season — These Christmas Party Outfits Will Turn Heads! - Dachbleche24

Be the Life of the Holiday Season — These Christmas Party Outfits Will Turn Heads! - Dachbleche24

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 Solución: Primero, calcula el área usando la fórmula de Herón.

📌 \[ s = \frac{25 + 30 + 35}{2} = 45 \, \text{ft} \]

📌 \[ \text{Área} = \sqrt{45(45-25)(45-30)(45-35)} = \sqrt{45 \times 20 \times 15 \times 10} = \sqrt{135000} \approx 367.42 \, \text{ft}^2 \]

📌 La altitud más corta es desde el vértice opuesto al lado más largo (35 pies):

📌 \[ \text{Altitud} = \frac{2 \times \text{Área}}{35} = \frac{2 \times 367.42}{35} \approx 21.02 \, \text{ft} \]

📌 La altitud más corta es aproximadamente \(\boxed{21.02}\) pies.

📌 Pregunta: Un geógrafo estudia una zona costera triangular donde el mar retira su línea de costa, formando un triángulo con lados de 10 km, 17 km y 21 km. ¿Cuál es el radio del círculo inscrito en esta forma retráctil?

📌 Solución: Primero, calcula el semiperímetro:

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We are given the equation in spherical coordinates:
ho = c \sin(\phi)
Recall the relationships between spherical and Cartesian coordinates:
x =
ho \sin\phi \cos heta, \quad y =
ho \sin\phi \sin heta, \quad z =
ho \cos\phi
Substitute \(
ho = c \sin(\phi)\) into the expressions:
x = c \sin(\phi) \cdot \sin(\phi) \cos heta = c \sin^2(\phi) \cos heta

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