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1 oz to gallon - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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f(x) = \left(\frac{u}{\frac{u^2 - 1}{2}}\right)^2 = \left(\frac{2u}{u^...
Now, since \(0 < x < \frac{\pi}{2}\), \(u = \sin x + \cos x = \sqrt{2}...
Let \(v = u^2\), so \(v \in (1, 2]\). Then:
f(x) = \frac{4v}{(v - 1)^2}
Let \(g(v) = \frac{4v}{(v - 1)^2}\). Find maximum on \(v \in (1, 2]\).
Take derivative:
g'(v) = \frac{4(v - 1)^2 - 4v \cdot 2(v - 1)}{(v - 1)^4} = \frac{4(v -...
For \(v > 1\), \(g'(v) < 0\), so \(g(v)\) is decreasing on \((1, 2]\)....
Wait — since derivative is negative, function decreases from \(v = 1^+...
But observe: as \(v \to 1^+\), g(v) → ∞? Let’s test:

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