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Home » \( R(20) = 400a + 20b + c = 50 \). - Dachbleche24

\( R(20) = 400a + 20b + c = 50 \). - Dachbleche24

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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Solve for \( x \) in the equation \( 2x^2 - 4x - 6 = 0 \).
Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)...
\( x = \frac{-(-4) \pm \sqrt{64}}{2 \times 2} = \frac{4 \pm 8}{4} \).
Solutions are \( x = \frac{4 + 8}{4} = 3 \) and \( x = \frac{4 - 8}{4}...
A company produces widgets that sell for $15 each. The cost to produce...
Revenue from selling \( x \) widgets is \( 15x \).
Break-even occurs when revenue equals cost: \( 15x = 5x + 200 \).
Solve for \( x \): \( 15x - 5x = 200 \), thus \( 10x = 200 \).
Divide both sides by 10: \( x = 20 \).
A sequence is defined by \( a_n = 3n^2 - 2n + 1 \). Find the 5th term.

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