DMCA
Contact
Privacy Policy

Home » = 1 \cdot 95 + 30 - Dachbleche24

= 1 \cdot 95 + 30 - Dachbleche24

📅 March 10, 2026 👤 scraface

Mar 10, 2026

Content is being prepared. Please check back later.

📚 You May Also Like These Articles

📌 $AB = \sqrt{(4-1)^2 + (5-2)^2 + (6-3)^2} = \sqrt{9 + 9 + 9} = \sqrt{27} = 3\sqrt{3}$

📌 $AC = \sqrt{(7-1)^2 + (8-2)^2 + (9-3)^2} = \sqrt{36 + 36 + 36} = \sqrt{108} = 6\sqrt{3}$

📌 $BC = \sqrt{(7-4)^2 + (8-5)^2 + (9-6)^2} = \sqrt{9 + 9 + 9} = \sqrt{27} = 3\sqrt{3}$

📌 We observe that $AB = BC = 3\sqrt{3}$, but $AC = 6\sqrt{3}$, so the three points are not equidistant. Thus, they cannot form a face of a regular tetrahedron. Therefore, the given points cannot be vertices of a regular tetrahedron with integer coordinates.

📌 However, if we reinterpret the question as seeking a fourth point $D = (x, y, z)$ such that all six edges $AB, AC, AD, BC, BD, CD$ are equal and the coordinates are integers, we proceed by solving the system:

📌 Let $AB = BC = CD = DA = DB = DC = s$. Then we solve the system of equations:

📌 Subtracting the first equation from the second and the second from the third gives linear equations in $x, y, z$. Subtracting the first from the second:

📌 [(x - 4)^2 - (x - 1)^2] + [(y - 5)^2 - (y - 2)^2] + [(z - 6)^2 - (z - 3)^2] = 0

🔥 Popular Posts

Second quarter decrease:
\(125,000 - (10\% imes 125,000) = 125,000 - 12,500 = 112,500\)
Profit at the end of the second quarter:
#### 112,500
Question:** A ball is thrown upwards with an initial velocity of 20 m/...
At maximum height, velocity \(v = 0\), time to reach it \(t = rac{v}{...
Now, calculate height using \(h = vt - rac{1}{2}gt^2\):
\(h = 20 imes 2.04 - rac{1}{2} imes 9.8 imes (2.04)^2\)
\(h = 40.8 - 20.4 = 20.4 \, ext{meters}\)
Question:** If an investment grows at a compound annual growth rate of...

📝 Recent Posts

$z = 90^\circ$: $\sin(180^\circ) = 0$, $\cos(90^\circ) = 0$ â 0 = 0...
$z = 270^\circ$: $\sin(540^\circ) = \sin(180^\circ) = 0$, $\cos(270^\c...
So all four satisfy? But earlier algebra says $\cos z (2\sin z - 1) =...
At $z = 270^\circ$, $\cos z = 0$, so included. But $\sin z = \sin(270^...
e 1/2$, but the equation $\cos z (2\sin z - 1) = 0$ only requires that...
\sin(2z) = \sin(540^\circ) = 0, \quad \cos(z) = \cos(270^\circ) = 0 \R...
So even though $\sin z
e 1/2$, the $\cos z = 0$ makes the whole expression zero. But our fact...
$\cos z = 0$ â $z = 90^\circ, 270^\circ$.
$\sin z = 1/2$ â $z = 30^\circ, 150^\circ$.

© 2026 Dachbleche24 · Powered by WordPress

Disclaimer: This site functions as an informational archive aggregating publicly available global death and memorial records. It is neither a news agency, media organization, nor an entertainment platform.